Start with an equilateral, but not necessary equiangular star. Proceed as in the case of the Reuleaux triangle. Specifically, use vertices of the star as centers to draw circular arcs of the radius equal to the side of the star. The arcs should connect pairs of adjacent vertices.
If we think of the arcs as bridging between the sides (or their extensions), we could draw arcs of a radius augmented by some positive quantity a. This creates gaps at the vertices of the star that could be filled with arcs of radius a.
Vertices of the star are draggable. The foregoing constructions will produce shapes of constant with as long as all sides cross each other and the number of vertices is odd.
The number of vertices in the star construction of shape of constant width is always odd.
Indeed, mark a vertex and the opposite arc. Count the number of vertices and arcs between the marked vertex and the marked arc. To the left of the marked vertex there will be, say, LV vertices and LA arcs. To the right of it there will be RV vertices and RA arcs. Since every arc follows a vertex and vice versa, LV = LA. Similarly, RV = RA. Since every arc lies opposite a vertex and vice versa, LV = RA and RV = LA. Therefore, all four numbers are equal to, say, N. Adding the marked vertex, we see that the total number of vertices equals 2N + 1.
There is a different approach to constructing the shapes of constant width. Known as the Crossed-Lines method, it is more general in that it uses a greater variety of radii than the star construction, which uses only two.
References
- M. Gardner, The Unexpected Hanging and Other Mathematical Diversions, The University of Chicago Press, 1991
- H. Rademacher and O.Toeplitz, The Enjoyment of Mathematics, Dover Publications, 1990
Copyright © 1996-2008 Alexander Bogomolny