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Forum URL:	http://www.cut-the-knot.org/cgi-bin/dcforum/forumctk.cgi
Forum Name:	Middle school
Topic ID:	39
Message ID:	3
#3, RE: Solution needed to question from Dudeney's Amusements in Mathematics Posted by alexb on Apr-10-01 at 06:32 PM In response to message #2 I made three assetions: One thing I suspect however is that both of you (Dudeney and you) can't be right. The four denominators 257, 809, 562, 795 are mutually prime, i.e., not two of them have common factors, except for 1. The fractions should add up to 1, right? You only addressed the last two :) So I am not quite certain whether your solution is right. Is it? Yes, I missed the last couple of sentences in Dudeney's problem. There were a few left over that were divided equally. So the sum must not be 1.