Hi all,

I'm sorry I've started this. I did not expect this will venture
outside of pure probabilities.

What makes me feel uncomfortable with the cakes is the fact that
when added across colors the probality goes over 1 (2/3+2/3 for 2
colors). Maybe it includes twice some combined colors probability?
There must be something.

Also, my mistake on asigning prob 1 to conditional P(B/notBB).
I wrongly thought that if we see Brown color, then it is 1. I am
corrected it is 1/4 (there are 4 sides on 2 not BB cakes and only
one side is B).

So it turns out that the probability in question will always be
2 / ( #of colors+1 ), which corresponds to having 2 cakes of the
same color on both sides and cakes of this color on one side and all
other colors on the other side ( AA,AA, AB, AC, AD, AE, AF -> 2/7 for
six colors A,B,C,D,E,F)

Bob G.