LAST EDITED ON Apr-11-01 AT 09:03 AM (EST)

LAST EDITED ON Apr-11-01 AT 08:46 AM (EST)

The problem is I can't start from ground 0. I do not know your course' syllabus, but I am pretty sure that a decent textbook with a title "Calculus" on the cover has some pertinent material.

Look for the limit as n goes to infinity of (1+1/n)n. As you like the number e, you'll be happy to learn that this is the limit of the sequence.

After that, proceed in steps:

lim (1+a/n)n = ea, a is constant.
lim ((n+1)/(n+3))n = lim ((1 - 2/(n+3))n+3)n/(n+3)