#0, Where do I start?
Posted by me on Jun-04-02 at 03:35 PM
4 (x+1)1/2 - 5(x+1)3/2 + (x+1)5/2 = 0
#1, RE: Where do I start?
Posted by bluediamond on Jun-04-02 at 09:10 AM
In response to message #0
I'm assuming you mean4 * (x+1)1/2 - 5 * (x+1)3/2 + (x+1)5/2 = 0 In that case, x = -1 is obviously a solution. For other solutions, assume that x is not equal to -1 and divide the entire thing by (x+1)1/2 to get a quadratic equation. dave
#2, RE: Where do I start?
Posted by Karl on Jun-05-02 at 09:10 AM
In response to message #0
First is that 4(x+1) * 1/2, that is multiplied by a half, or 4(x+1)^1/2, that is to the power one half?
#3, RE: Where do I start?
Posted by sapforhire on Jun-05-02 at 09:10 AM
In response to message #0
Distributing and combining like terms gives you -3x-3=0. Another way is to think about the (x+1) and realize that small equation appears in each part of the equation; therefore if x+1=0 then the whole equation equals 0
#4, RE: Where do I start?
Posted by murat on Jun-06-02 at 09:10 AM
In response to message #0
it is very simple actually. if you look carefully you should realise that the answer is -1. because if you replace x by -1 every paranthesis becomes 0(zero) so it satisfies the equation. but if you need the proof...first lets open the eq. (4x+4)/2 -(15x+15)/2 + (5x+5)/2 = 0 multiply everything by 2 and get rid of the paranthesis 4x+4-15x-15+5x+5=0 and just solve the eq. -6x = 6 x= -1 that is it... hope it helps.
murat
#5, RE: Where do I start?
Posted by emily on Jun-07-02 at 03:17 PM
In response to message #0
i dont know... im not 2 good @ math, even though i have an a in the class! hehe... email me if u REALLY NEEDhelp... im good w/ fractions.. if that helps.
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