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Mathematical induction

Mathematical Induction (MI) is an extremely important tool in Mathematics.

First of all you should never confuse MI with Inductive Attitude in Science. The latter is just a process of establishing general principles from particular cases.

MI is a way of proving math statements for all integers (perhaps excluding a finite number.) [1] says:

Statements proven by math induction all depend on an integer, say, n. For example,

(1) 1 + 3 + 5 + ... + (2n-1) = n2
(2) If x1, x2, ..., xn > 0 then (x1 + x2 + ... + xn)/n (x1·x2·...·xn)1/n

etc. n here is an "arbitrary" integer.

It's convenient to talk about a statement P(n). For (1), P(1) says that 1 = 12 which is incidently true. P(2) says that 1 + 3 = 22, P(3) means that 1 + 3 + 5 = 32. And so on. These particular cases are obtained by substituting specific values 1, 2, 3 for n into P(n).

Assume you want to prove that for some statement P, P(n) is true for all n starting with n = 1. The Principle (or Axiom) of Math Induction states that, to this end, one should accomplish just two steps:

  1. Prove that P(1) is true.
  2. Assume that P(k) is true for some k. Derive from here that P(k+1) is also true.

The idea of MI is that a finite number of steps may be needed to prove an infinite number of statements P(1), P(2), P(3), ....

Let's prove (1). We already saw that P(1) is true. Assume that, for an arbitrary k, P(k) is also true, i.e. 1 + 3 + ... + (2k-1) = k2. Let's derive P(k+1) from this assumption. We have

1 + 3 + ... + (2k-1) + (2k+1)= [1 + 3 + ... + (2k-1)] + (2k+1)
 = k2 + (2k+1)
 = (k+1)2

Which exactly means that P(k+1) holds. (For 2k+1 = 2(k+1)-1.) Therefore, P(n) is true for all n starting with 1.

Intuitively, the inductive (second) step allows one to say, look P(1) is true and implies P(2). Therefore P(2) is true. But P(2) implies P(3). Therefore P(3) is true which implies P(4) and so on. Math induction is just a shortcut that collapses an infinite number of such steps into the two above.

In Science, inductive attitude would be to check a few first statements, say, P(1), P(2), P(3), P(4), and then assert that P(n) holds for all n. The inductive step "P(k) implies P(k+1)" is missing. Needless to say nothing can be proved this way.

Remark

  1. Often it's impractical to start with n = 1. MI applies with any starting integer n0. The result is then proven for all n from n0 on.
  2. Sometimes, instead of 2., one assumes 2':

    Assume that P(m) is true for all m < (k+1).

    Derive from here that P(k+1) is also true. The two approaches are equivalent, because one may consnider a statement Q: Q(n) = P(1) and P(2) and ... and P(n), so that Q(n) is true iff P(1), P(2), ..., P(n) are all true.

There are other examples proven by MI:

  1. A 1-1 correspondence
  2. An Extension of van Schooten's Theorem
  3. An infinite exponent
  4. Another pigeonhole problem
  5. A Problem of Divisibility by 5n
  6. Binary Euclid's algorithm
  7. Book Index Range
  8. Breaking Chocolate Bars
  9. Committee Chairs
  10. Constructible Numbers
  11. Construction Problem
  12. Continued Fractions
  13. Counting Triangles
  14. Counting Triangles II
  15. Cutting Squares
  16. Diagonal Count
  17. Difference of the Cantor Sets
  18. Euclid's Algorithm
  19. Farey series
  20. Fractions on a Binary Tree II
  21. Geometric Illustration of a Convergent Series
  22. Golomb's inductive proof of a tromino theorem
  23. Groups of Permutations
  24. Guessing Two Consecutive Integers
  25. Hamming and Levenshtein distance functions
  26. Inequality 1/2·3/4·5/6· ... ·99/100 < 1/10
  27. Inequality (1 + 1-3)(1 + 2-3)(1 + 2-3)...(1 + n-3) < 3
  28. Inequality 1 + 2-2 + 3-2 + 4-2 + ... + n-2 < 2
  29. Inequality between arithmetic and geometric means
  30. Infinite Latin Squares
  31. Infinitude of Primes Via Fermat Numbers
  32. Infinitude of Primes Via *-Sets
  33. Integers and Rectangles: a Proof by Induction
  34. Integral Domains: Remarks and Examples
  35. Josephus problem
  36. Linear Functions
  37. Marriage Problem
  38. Mathematical Induction
  39. Mathematicians Doze Off
  40. Morley's Pursuit of Incidence
  41. Pennies in Boxes
  42. Pigeonhole problem
  43. Pigeonhole principle complements math induction
  44. Poncelet Theorem
  45. Prim's and Kruskal's algorithms find a minimum spanning tree
  46. Problem on an Infinite Checkerboard
  47. Property of irriducible fractions on the Stern-Brocot tree
  48. Property of the Powers of 2
  49. Sierpinski Gasket
  50. Sierpinski Gasket and Tower of Hanoi
  51. Simple Cellular Automaton
  52. Solitaire on the Circle
  53. Splitting piles
  54. Stern-Brocot Tree
  55. Stern-Brocot Tree II
  56. Strange Integers: Divisors and Primes
  57. The Somos sequences
  58. Ways To Count

Reference

  1. D. Fomin, S. Genkin, I. Itenberg, Mathematical Circles (Russian Experience), AMS, 1996
  2. R. Graham, D. Knuth, O. Patashnik, Concrete Mathematics, 2nd edition, Addison-Wesley, 1994.
  3. R.Courant and H.Robbins, What is Mathematics?, Oxford University Press, 1996

On the Web

  1. An online and iPod video by Julio de la Yncera

 

 

Copyright © 1996-2008 Alexander Bogomolny

28781340Page copy protected against web site content infringement by Copyscape


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